要仅更新单个值并在MongoDB中对其进行递增,请使用$inc和update()。让我们创建一个包含文档的集合-
> db.demo698.insertOne({Score:78}); { "acknowledged" : true, "insertedId" : ObjectId("5ea6d8a4551299a9f98c9398") } > db.demo698.insertOne({Score:56}); { "acknowledged" : true, "insertedId" : ObjectId("5ea6d8a7551299a9f98c9399") } > db.demo698.insertOne({Score:65}); { "acknowledged" : true, "insertedId" : ObjectId("5ea6d8aa551299a9f98c939a") } > db.demo698.insertOne({Score:88}); { "acknowledged" : true, "insertedId" : ObjectId("5ea6d8b0551299a9f98c939b") }
在find()方法的帮助下显示集合中的所有文档-
> db.demo698.find();
这将产生以下输出-
{ "_id" : ObjectId("5ea6d8a4551299a9f98c9398"), "Score" : 78 } { "_id" : ObjectId("5ea6d8a7551299a9f98c9399"), "Score" : 56 } { "_id" : ObjectId("5ea6d8aa551299a9f98c939a"), "Score" : 65 } { "_id" : ObjectId("5ea6d8b0551299a9f98c939b"), "Score" : 88 }
以下是仅增加单个值的查询-
> db.demo698.update({_id:ObjectId("5ea6d8b0551299a9f98c939b")},{$inc:{Score:12}}); WriteResult({ "nMatched" : 1, "nUpserted" : 0, "nModified" : 1 })
在find()方法的帮助下显示集合中的所有文档-
> db.demo698.find();
这将产生以下输出-
{ "_id" : ObjectId("5ea6d8a4551299a9f98c9398"), "Score" : 78 } { "_id" : ObjectId("5ea6d8a7551299a9f98c9399"), "Score" : 56 } { "_id" : ObjectId("5ea6d8aa551299a9f98c939a"), "Score" : 65 } { "_id" : ObjectId("5ea6d8b0551299a9f98c939b"), "Score" : 100 }