对于给定的长整数n,编写一个程序以查找奇数位和偶数位总和之间的差是否为0。索引从0开始。
n = 1212112
Sum of odd position elements
= 2 + 2 + 1
= 5
Sum of even position elements
= 1 + 1 + 1 + 2
= 5
Difference
= 5 - 5
= 0
Output
= Yes
以下是Java中的程序,用于查找所需的输出。
class JavaTester {
public static int difference(int n){
return (n % 11);
}
public static void main(String args[]){
int n = 1212112;
System.out.println("Number: " + n);
System.out.println(difference(n) == 0 ? "Yes" : "No");
n = 12121121;
System.out.println("Number: " + n);
System.out.println(difference(n) == 0 ? "Yes" : "No");
}
}
输出结果
Number : 1212112
Output: Yes
Number : 12121121
Output: No